Find all solutions to the equation csc x (2sinx-Sqrt 2) = 0

The solution would be like this for this specific problem:

x = Pi/4 + 2kPi and 3Pi/4 + 2kPi, where k is any positive integer

If the solution continued forever, any positive integer will create just one more rotation 2pi, 4pi, 6pi, so on and so forth, thus, giving all of them the same value.