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14 December, 13:46

A triangle has sides of length 5, 8, and 10. What is the measure of its largest angle?

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  1. 14 December, 17:07
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    We'll use the Law of Cosines

    We'll call

    side a = length 5

    side b = length 8

    side c = length 10

    and their corresponding angles as A, B and C

    "C" would be the largest angle

    cos (C) = (a^2 + b^2 - c^2) / 2 * a * b

    cos (C) = (5^2 + 8^2 - 10^2) / 2 * 5 * 8

    cos (C) = 25 + 64 - 100 / 80

    cos (C) = - 11 / 80

    cos (C) = - 0.1375

    arc cosine (-0.1375) = 97.903 Degrees

    The largest angle is 97.903 Degrees
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