A balloon has a volume of 2.9 l at 320 kelvin. if the temperature is raised to 343 k, what will its volume be?

To answer this problem, we assume that the gas being referred to in the problem is ideal. If that is the case, we will be able to use the ideal gas law given to be,

PV = nRT

The equation that would best relate the volume and temperature of the ideal gas is,

V₁T₂ = V₂T₁

Substituting the known values,

(2.9L) (343 K) = (V₂) (320 K)

The value of V₂ is 3.11L.