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14 October, 14:08

Evaluate x/y + 3z^2 for x = 2/3, y = 6/7, and z=3

a. 250/9

b. 169/9

c. 9/250

d. 9/169

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Answers (2)
  1. 14 October, 16:11
    0
    remember that (a/b) / (c/d) = (a/b) (d/c) = (ad) / (bc)

    (2/3) / (6/7) + 3 (3) ^2=

    (2/3) (7/6) + 3 (9) =

    (2*7) / (3*6) + 27=

    (14/18) + 27=

    (7/9) + 27=

    7/9+243/9=

    250/9

    answer is A
  2. 14 October, 17:37
    0
    x/y + 3z^2 for x = 2/3, y = 6/7, and z=3

    =2/3 / 6/7 + 3 (3^2)

    =2/3 * 7/6 + 3 (9)

    = 7/9 + 27

    = 7/9 + 243/9

    = 250/9

    answer is a. 250/9
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