12 yellow balls and 9 red balls are placed in an urn. Two balls are then drawn in succession without replacement. What is the probability that the first ball drawn is a red ball if the second ball drawn is yellow? a) 0.8333 b) 0.4500 c) 0.5714 d) 0.4762 e) 0.2593 f) None of the abov

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Mathematics

Antoine

1 December, 04:27

12 yellow balls and 9 red balls are placed in an urn. Two balls are then drawn in succession without replacement. What is the probability that the first ball drawn is a red ball if the second ball drawn is yellow? a) 0.8333 b) 0.4500 c) 0.5714 d) 0.4762 e) 0.2593 f) None of the abov

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Jaquan Ashley · Answer 1

If 21 balls are placed in an urn, 12 being yellow, and 9 being red, the probability that the first ball drawn is a red ball is always 9/21 or approximately 0.4286. This answer is true regardless of what color the second ball is. The answer to this question is f) None of the above.