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28 February, 17:16

Mike and adam left a bus terminal at the same time and traveled in opposite directions. mike's bus was in heavy traffic and had to travel 20 mi/h slower than adam's bus. after 3 hours, their buses were 270 miles apart. how fast was each bus going?

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  1. 28 February, 19:33
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    Adam's bus speed = a

    mike's bus speed = m

    total distace = t

    m = a - 20

    after 3 hour:

    3 * (m + a) = t

    3 * (m + a) = 270

    3m + 3a = 270

    [ 3 * (a - 20) ] + [ 3 * a ] = 270

    [ 3a - 60 ] + 3a = 270

    3a - 60 + 3a = 270

    3a + 3a = 270 + 60

    6a = 330

    their speed:

    a = 55

    m = 55 - 20 = 35
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