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10 January, 20:06

Determine if the lines are parallel, perpendicular, or neither x-3y = 15 and y = - 3+4

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  1. 10 January, 22:05
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    If the second equation is y=-3x+4 then they would be parallel and I found that by turning the first equation into y=mx+b and you subtract x from both sides of the equation and get - 3y=-x+15 and then you divide both sides of the equation by - 3 to get the y by itself and that turns into y=1/3x-5 and since 1/3 is the reciprocal of - 3 they are perpendicular.
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