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17 December, 00:08

Show all work. What are the zeros of the function?

f (x) = 2x^2 - 8x - 10

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  1. 17 December, 00:47
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    (2x² - 8x - 10) : 2 = 0

    x² - 4x - 5 = 0

    x² + x - 5x - 5 = 0

    x (x+1) - 5 (x+1) = 0

    (x+1) (x-5) = 0

    x+1 = 0 or x-5 = 0

    x = - 1 or x = 5

    S = {-1; 5}
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