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16 September, 00:21

6*11=66,89*101=8989,706*1001=706706. next two sequence are?

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  1. 16 September, 00:30
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    The solution would be like this for this specific problem:

    2nd factor product goes like this: 11, 101, 1001, so the next 2nd factor would be 10001.

    1st factor can be solved thru using a polynomial function.

    (n) = 267n² - 718n + 457

    FirstFactor (4) = 1857

    So, the 4th product is 1857 * 10001 = 18571857
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