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6 June, 08:26

A landscape architect is planning a new nature in the middle of an urban campus. she wants the length to be twice the width and wants to put a 3foot high retaining wall around the perimeter. there will be 300 total feet of wall installed. How wide will this area be

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  1. 6 June, 08:48
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    In order to find the width, we will first allot variables to the unknown quantities.

    Let the width be x

    The length then becomes 2x

    The length of the wall installed will be equivalent to the perimeter of the area. Let us assume that the area is rectangular. Thus,

    2 (length + width) = perimeter

    2 (2x + x) = 300

    3x = 150

    x = 50

    The width of the area is 50 feet.
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