If the quadratic formula is used to find the roots of the equation x^2-6x-19=0, the correct roots are?

X² + px + q = 0

x² - 6x - 19 = 0

x = 1 (-p + √p² - 4q)

2

x = 1 ( - (-6) + √ - (6) ² - 4 (-19)

2

x = 1 (6 + √-36 + 76)

2

x = 1 (6 + √40)

2

x = 1 (6 + √4 * 2 * 5)

2

x = 1 (6 + √4 √2 √5)

2

x = 1 (6 + 2 √2 √5)

2

x = 1 (6 + 2 √2 √5) x = 1 (6 - 2 √2 √5)

2 2

x = 1 (8 √2 √5) x = 1 (4 √2 √5)

2 2

x = 4 (0.5) (1.25) x = 2 (0.5) (1.25)

x = 2.5 x = 1.25