The circular bull's-eye of an archery target has a diameter of 24 cm, which is surrounded by 4 concentric rings with a width of 12 cm each. Draw the target in a coordinate plane with center at the origin. Write the equations of the circles that form the boundaries of the different regions of the target.

Question

Mathematics

Angelica Rhodes

12 January, 04:51

The circular bull's-eye of an archery target has a diameter of 24 cm, which is surrounded by 4 concentric rings with a width of 12 cm each. Draw the target in a coordinate plane with center at the origin. Write the equations of the circles that form the boundaries of the different regions of the target.

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Chump · Answer 1

Given:

Target bull's eye with a diameter of 24 centimeters.

4 concentric rings with a width of 12 cm each.

First circle, d1 = 24 cm

2nd circle, d2 = 24 + (12*2) = 48 cm

3rd circle, d3 = 24 + (12*3) = 60 cm

4th circle, d4 = 24 + (12*4) = 72 cm