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3 July, 13:02

The first aircraft has 75 more seats than the second aircraft. The third aircraft has 49 fewer seats than the second aircraft. If their total number of seats is 401 , find the number of seats for each aircraft.

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  1. 3 July, 16:42
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    1st = 75+x

    2nd = x

    3rd = x-49

    401 = 75 + x + x + + x-49

    401 = 75+3x-49

    401 = 3x+26

    375=3x

    x=375/3 = 125

    1st = 125+75 = 200

    2nd = 125

    3rd = 125-49 = 76

    200 + 125 + 76 = 401
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