Identify two additional values for x and y in a direct variation relationship where y = 11 when x=18

In a direct variation relationship the values must satisfy that y = kx. This si y is always a constant value (k) times x.

So, you can find multiple values that meet this:

y = kx = > k = y / x = 11 / 18

=> y = (11/18) x

Now you can give any value to x and fint the value of x that satisfy the relationship:

x y = (11/18) x

1 11/18

2 11/18 * 2 = 11/9

18 11/18 * 18 = 11

36 11/18 * 36 = 22

So, there you have several additional values for x and y in the same relationship that y = 11 and x = 18, and you can find many more using the same rule: y = (11/18) * x