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13 September, 17:17

The range of the function f (k) = k^2 + 2k + 1 is {25, 64}. What is the function's domain?

A. {5,8}

B. {-5, - 8}

C. {3, 8}

D. {4, 7}

E. {4, 8}

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Answers (1)
  1. 13 September, 18:36
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    k^2 + 2k + 1 = 25

    k^2 + 2k + 1 - 25 = 0

    k^2 + 2k - 24 = 0

    (k - 4) (k + 6) = 0

    k - 4 = 0; k = 4

    k + 6 = 0; k = - 6

    k^2 + 2k + 1 = 64

    k^2 + 2k + 1 - 64 = 0

    k^2 + 2k - 63 = 0

    (k - 7) (k + 9) = 0

    k - 7 = 0; k = 7

    k + 9 = 0; k = - 9

    x = - 9, - 6, 4, 7

    answer

    D. {4, 7}
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