What are the solutions for x when y is equal to 0 in the quadratic function y=x^2-8x

I would use the quadratic formula for this:

x = - b ± √b² - 4ac over 2a

x = 8 ± √64 - 4 (1) (0) over 2 (1)

x = 8 ± √64 over 2

x = 8 ± 8 over 2 [simplify]

x = 4 ± 4

x1 = 4 + 4 x2 = 4 - 4

x1 = 8 x2 = 0

Thus, the solutions for x would be 0 and 8.