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22 March, 19:43

Jun has 240 meters of fencing to make a rectangular enclosure. she also wants to use some fencing to split the enclosure into two parts with a fence parallel to two of the sides. what dimensions should the enclosure have to have the maximum possible area? (enter your answers as a comma-separated list.)

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  1. 22 March, 22:51
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    Let x meter, y meter be the dimension.

    3x+2y=240

    y=-3x/2 + 120

    The area = - 3 (x^2) / 2 + 120x

    =-3/2 (x^2-80x)

    =-3/2 (x-40) ^2 + 2400

    The area is maximized when x=40

    Then y=-3 (40) / 2 + 120 = 60

    Hence the required dimension is 40meters, 60meters
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