Which binomial is a factor of 9 x 2 - 64

3x-8

9x-32

3x+32

9x+8

9x^2-64

Using:

a^2-b^2 = (a-b) (a+b), with:

a^2=9x^2→sqrt (a^2) = sqrt (9x^2) →a=sqrt (9). sqrt (x^2) →a=3x

b^2=64→sqrt (b^2) = sqrt (64) →b=8

9x^2-64 = (3x-8) (3x+8)

Then the factors of 9x^2-64 are 3x-8 and 3x-8

Answer: First option 3x-8