Solve the system by substitution y=x^2-2x+1 y=2x+1

Y=y so

x^2-2x+1=2x+1

x^2-4x=0

x (x-4) = 0

So the x values will be x=0 and 4, now you need the y values ...

y=2x+1, y (0) = 1 and y (4) = 9, so the two solutions are:

(0,1) and (4,9)