What is sum of the area under the standard normal curve to the left of z = - 1 and to the right og z = 1.25?

From standard tables, the area to the left of z = - 1 is

A₁ = 0.1587

The area to the left of z = 1.25 is

A₂ = 0.8944

Therefore the area to the right of z = 1.25 is

1 - A₂ = 0.1056

The sum of the areas to the left of z = - 1 and to the right of z = 1.25 is

0.1587 + 0.1056 = 0.2643

Answer: 0.2643