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31 January, 14:35

If 3000 ft3

of air is crossing an evaporator coil and is

cooled from 75°F to 55°F, what would be the volume of

air, in ft3

, exiting the evaporator coil

+1
Answers (1)
  1. 31 January, 17:20
    0
    Charles law:

    V1/T1=V2/T2

    where T is in deg. K.

    75°F=297.04°K

    55°F=285.92°K

    =>

    V2=V1/T1*T2

    =3000 * (285.92/297.4)

    =2887.8 c. f.
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