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6 December, 05:35

The perimeter of a rectangular house is 122fr the width is 5ft less than the length find the length and width

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Answers (2)
  1. 6 December, 09:09
    0
    Hello,

    Let's w the width, l the length, p the perimeter.

    w=l-5

    p=2 (l+w) = 2 (l+l-5) = 4l-10

    4l-10=122

    ==>4l=122+10

    ==>4l=132

    ==>l=132/4

    ==>l=33

    So w=33-5=28

    Proof:

    2 * (33+28) = 2*61=122
  2. 6 December, 09:15
    0
    Length x width is my suggestion
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