Solve open parentheses square root of 7 close parentheses to the 6 x power = 49x-6.
x = negative 21 over 2
x = - 6
x = negative 6 over 5
x = - 12
Answers (1)
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Solve open parentheses square root of 7 close parentheses to the 6 x power = 49x-6. x = negative 21 over 2 x = - 6 x = negative 6 over 5 x ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers
You Might be Interested in
Determine if the sequence is arithmetic. - 9, - 109, - 209, - 309
Answers (1)
How many Times does 3 go into 1.4
Answers (1)
During the new year celebration there are orange, green purple, and blue fireworks. In how many different orders can the different colors of fireworks appear?
Answers (1)
A triangle has side lengths of 12 cm, 35 cm, and 37 cm. Classify it as acute, obtuse, or right. acute obtuse right
Answers (2)
45*5:45+3455-455+75456-88
Answers (2)
New Questions in Mathematics
What is the domain, range, and function for (-6, 4), (5, - 1), (0, 3), (-2, 4)
Answers (1)
Find the nth term in the following sequence: 10, 19, 34, 55
Answers (1)
How to subtract 23 from 71 is like subtracting 3 from 71? How is it different from subtracting 3 from 71? Explain.
Answers (1)
12per cent of 23563412
Answers (1)
I=/sqrt{-1}i = - 1 i, equals, square root of, minus, 1, end square root, what is the sum (7+3i) + (-8+9i) (7+3i) + (-8+9i) left parenthesis, 7, plus, 3, i, right parenthesis, plus, left parenthesis, minus, 8, plus, 9, i, right parenthesis?
Answers (1)