Find the vertex for y=3x^2-6x+5

The x value of the vertex in

ax^2+bx+c is - b/2a

y value is just sub for x

3x^2-6x+5

x value of vertex is - (-6) / (2*3) = 6/6=1

sub back

y=3 (1) ^2-6 (1) + 5

y=3 (1) - 6+5

y=3-1

y=2

vertex is (1,2)