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Mathematics
Muffy
3 October, 14:30
Find the vertex for y=3x^2-6x+5
+5
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Royce
3 October, 15:56
0
The x value of the vertex in
ax^2+bx+c is - b/2a
y value is just sub for x
3x^2-6x+5
x value of vertex is - (-6) / (2*3) = 6/6=1
sub back
y=3 (1) ^2-6 (1) + 5
y=3 (1) - 6+5
y=3-1
y=2
vertex is (1,2)
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