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3 October, 14:30

Find the vertex for y=3x^2-6x+5

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  1. 3 October, 15:56
    0
    The x value of the vertex in

    ax^2+bx+c is - b/2a

    y value is just sub for x

    3x^2-6x+5

    x value of vertex is - (-6) / (2*3) = 6/6=1

    sub back

    y=3 (1) ^2-6 (1) + 5

    y=3 (1) - 6+5

    y=3-1

    y=2

    vertex is (1,2)
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