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14 December, 07:13

Solve the system algebraically.

x - y + 2z = - 3

2x + 2y - z = - 3

3x + 2y = 8

No solution

(-42, 67, 53)

Infinite solutions

(43, - 57, 63)

+1
Answers (1)
  1. 14 December, 09:33
    0
    1x - 1y + 2z = - 3 → 1x - 1y + 2z = - 3 → 2x - 2y + 4z = - 6

    2x + 2y - 1z = - 3 → 2x + 2y - 1z = - 3 → 2x + 2y - 1z = - 3

    3x + 2y + 0z = 8 4x + 3z = - 9

    1x - 1y + 2z = - 3

    2x + 2y - 1z = - 3 → 2x + 2y - 1z = - 3 → - 2x - 2y + 1z = 3

    3x + 2y + 0z = 8 → 3x + 2y + 0z = 8 → 3x + 2y + 0z = 8

    x + z = 11

    4x + 3z = - 9 → 4x + 3z = - 9

    1x + 1z = 11 → 4x + 4z = 44

    -z = - 53

    -1 - 1

    z = 53

    x + z = 11

    x + 53 = 11

    - 53 - 53

    x = - 42

    3x + 2y = 8

    3 (-42) + 2y = 8

    -126 + 2y = 8

    + 126 + 126

    2y = 134

    2 2

    y = 67

    (x, y, z) = (-42, 67, 53)

    The answer is B.
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