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15 August, 19:02

Two similar parallelograms have areas 125 m 2 and 80 m 2. the height of the larger parallelogram is 10 m. what are the lengths of the bases of both parallelograms? solved

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  1. 15 August, 20:37
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    To solve this problem you must follow the proccedure shown below:

    You have that:

    - Two similar parallelograms have areas 125 m².

    - The height of the larger parallelogram is 10 m. Then, you have:

    125=10x

    x: the base of the larger parallelogram

    x=125/10

    x=12.5 m

    The ratio is:

    b/h=12.5/10

    b=1.25h

    - The area of the smaller parallelogram is 80 m ², then, you have:

    80=bh

    When you susbstitute b=1.25h into 80=bh, you obtain the value of "h":

    80 = (1.25h) h

    80=1.25h ²

    h=√ (80/1.25)

    h=8

    Then, the other base is:

    b=1.25 (8)

    b=10 m

    The answer is: The base of the smaller parallelogram is 10 m and the base of the larger parallelogram is 8 m.
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