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28 July, 10:38

Consider the expression. When using the inspection method, the number you would add to (and subtract from) the constant term of the numerator so the polynomial in the numerator will have (x + 3) as a factor is

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  1. 28 July, 12:13
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    (x+3) (x+k) = x^2 + (3+k) x + 3k

    3+k=1

    k=-2

    (x+3) (x-2) = x^2 + x - 6

    (x^2 + x - 6) - (x^2 + x - 10) = 4

    add 4.
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