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6 December, 23:09

How to put (a^-1) / ((b^-1) (square root of a)) in ca^pb^q form

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  1. 7 December, 01:21
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    (a^-1) / [ (b^-1) sqrt a] or [ (a^-1) / (b^-1) ]sqrt a (a^-1) / [ (b^-1) sqrt a] = a^ (-3/2) b [ (a^-1) / (b^-1) ]sqrt a = a^ (-1/2) b
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