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14 August, 03:51

What is the derivative of sqrt7 times x + sqrt2x

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  1. 14 August, 07:15
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    I guess you mean the derivative of:

    √7x + √2x, if so then:

    Remember that the derivative of √u = 1 / (2√u). u'

    if 7x = u, then u' = 7, hence the derivative of √7x is 7 / (2√7x)

    Use same logic for √2x and you will find:

    y' = 7 / (2√7x) + x/√2x
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