An suv is traveling at a speed of 18 m/s. If the sub has a mass of 1,550 kg, what force must be applied to stop it in 8 seconds?

First we have to find for the acceleration with the equation (Vo - V1) / t

Given: V1 = 18 m/s

Vo = 0 m/s

t=8

(0-18m/s) / 8 = - 2.25m/s^2

Then we compute for the Force. F=ma

F=1550*-2.25m/s^2

F = - 3487.5 N

Thus, the answer is - 3487.5 N