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31 May, 14:45

The mpg (miles per gallon for a certain compact car is normally distributed with a mean of 31 and a standard deviation of 0.8. what is the probability that the mpg for a randomly selected compact car would be less than 32?

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  1. 31 May, 16:56
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    For this Q:

    mean=31

    st. dev.=0.8

    x=32

    Calculate z-score:

    z = (x-m) / s = (32-31) / 0.8=1.25

    This z-score value corresponding to the probability of 0.8944
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