At what projection angle will the range of a projectile equal to 6 times its maximum height?

The formula for maximum height is:

H = v²sin²θ/2g

The formula for range is:

R = v²sin (2θ) / g

The relationship between the two is written as:

R = 6H

v²sin (2θ) / g = 6 (v²sin²θ/2g)

v²sin (2θ) / g = 3v²sin²θ/g)

Cancelling out like terms,

sin (2θ) = 3sin²θ

Solving for θ using a scientific calculator,

θ = 33.7°

I not sure but it might be 60 kilogrames