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19 April, 17:23

Find the 2nd term of an arithmetic sequence with t5 = 3 and t7 = 7?

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  1. 19 April, 19:22
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    Let a be the first term and d be the common difference

    t5 = 3 = a + 4d

    t7 = 7 = a + 6d

    a + 6d - a - 4d = 7 - 3

    2d = 4

    d = 2

    Sub d = 2,

    3 = a + 4 (2)

    a = - 5

    t2 = a + d

    t2 = - 5 + 2

    t2 = - 3
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