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10 February, 05:32

Solve the equation on the interval [0,2pi) 4sin^2x-3=0

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  1. 10 February, 07:22
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    4sin²x-3=0

    4sin²x=3

    sin²x=3/4

    sinx=√3/2 or - √3/2

    x=π/3, 2π/3, 4π/3, or 5π/3
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