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Mathematics
Timothy Hurst
4 December, 23:49
The zeros for f (x) = x^4-4x^3-9x^2+36x are
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Alondra Bautista
5 December, 00:51
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X^4 - 4x^3 - 9x^2 + 36x = 0
x (x^3 - 4x^2 - 9x + 36) = 0
x (x^2 (x - 4) - 9 (x - 4) = 0
x (x + 3) (x - 3) (x - 4) = 0
the zeroes are - 3, 0, 3, 4 Answer
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