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7 December, 19:39

Solve the given equation on the domain [0,2π]: 2sinx-sqrt (2) = 0

sqrt=squareroot

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  1. 7 December, 20:05
    0
    2 sin (x) - √2 = 0

    2 sin (x) = √2

    sin (x) = (1/2) √2

    x = sin⁻¹ (1/2 √2) = 45° and 135°.
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