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Mathematics
Alberto Wiley
18 December, 19:46
Q bisects PR, PQ=3y, and PR=42. Find y and QR.
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Blimpie
18 December, 20:05
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|PR| = |PQ| + |QR|; |PQ| = |QR| conclusion |PR| = 2|PQ|
|PQ| = 3y; |PR| = 42; |QR|=?
subtitute
42 = 2 (3y)
6y = 42 |divide both sides by 6
y = 7
|QR| = 3 (7) = 21
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