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18 December, 19:46

Q bisects PR, PQ=3y, and PR=42. Find y and QR.

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  1. 18 December, 20:05
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    |PR| = |PQ| + |QR|; |PQ| = |QR| conclusion |PR| = 2|PQ|

    |PQ| = 3y; |PR| = 42; |QR|=?

    subtitute

    42 = 2 (3y)

    6y = 42 |divide both sides by 6

    y = 7

    |QR| = 3 (7) = 21
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