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4 January, 11:05

Not including myself and 1, my factors are 2, 3, 4, 6, 8, 12, 16, 24, 32, and 48. What number am I?

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Answers (2)
  1. 4 January, 13:15
    0
    2=2

    3=3

    4=2*2

    6=2*3

    8=2*2*2

    12=2*2*3

    16=2*2*2*2

    24=2*2*2*3

    32=2*2*2*2*2

    48=2*2*2*2*3
  2. 4 January, 14:42
    0
    2=2

    3=3

    4=2*2

    6=2*3

    8=2*2*2

    12=2*2*3

    16=2*2*2*2

    24=2*2*2*3

    32=2*2*2*2*2

    48=2*2*2*2*3

    This is called the prime factors of these numbers. As you can see 3 only appears once for a single number. The maximum number of 2s is 5.

    Thus the solution is 2*2*2*2*2*3=96
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