Not including myself and 1, my factors are 2, 3, 4, 6, 8, 12, 16, 24, 32, and 48. What number am I?

Question

Mathematics

Crystal Graves

4 January, 11:05

Not including myself and 1, my factors are 2, 3, 4, 6, 8, 12, 16, 24, 32, and 48. What number am I?

+4

Answers (2)

Know the Answer?

Karma Petty · Answer 1

2=2

3=3

4=2*2

6=2*3

8=2*2*2

12=2*2*3

16=2*2*2*2

24=2*2*2*3

32=2*2*2*2*2

48=2*2*2*2*3

Melanie Golden · Answer 2

2=2

3=3

4=2*2

6=2*3

8=2*2*2

12=2*2*3

16=2*2*2*2

24=2*2*2*3

32=2*2*2*2*2

48=2*2*2*2*3

This is called the prime factors of these numbers. As you can see 3 only appears once for a single number. The maximum number of 2s is 5.

Thus the solution is 2*2*2*2*2*3=96