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7 October, 16:25

What is a number greater than 1,000 whose prime factorization contains 1 prime number that does not repeat, 1 prime number that repeats three times, and 1 prime number that repeats twice

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  1. 7 October, 17:10
    0
    Find big prime numbers

    we need 3 of them

    23 and 19 and 101

    so we can do

    does not repeat

    does reapat 3 times

    repeats twice

    (23) (19³) (101³) = 8554589203

    there, that's a possible number

    if ya wanted a smaller one then

    2 and 5 and 11 are prime

    (2) (5³) (11²) = 30250

    that's another possible number
  2. 7 October, 20:19
    0
    You could just fill in the spaces.

    So for the prime number that doesn't repeat, you can just say a random prime number, say like 7.

    For the prime number that repeats 3 times, say like 11.

    And the prime number that repeats twice, you can just say something like 13.

    Then it would be 7 * 11 * 11 * 11 * 13 * 13, which the solution would be 1,574,573, above 1000.
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