What is a number greater than 1,000 whose prime factorization contains 1 prime number that does not repeat, 1 prime number that repeats three times, and 1 prime number that repeats twice

Find big prime numbers

we need 3 of them

23 and 19 and 101

so we can do

does not repeat

does reapat 3 times

repeats twice

(23) (19³) (101³) = 8554589203

there, that's a possible number

if ya wanted a smaller one then

2 and 5 and 11 are prime

(2) (5³) (11²) = 30250

that's another possible number

You could just fill in the spaces.

So for the prime number that doesn't repeat, you can just say a random prime number, say like 7.

For the prime number that repeats 3 times, say like 11.

And the prime number that repeats twice, you can just say something like 13.

Then it would be 7 * 11 * 11 * 11 * 13 * 13, which the solution would be 1,574,573, above 1000.