Differentiate the function f (x) = log[2] (1-3x)

We express the expression as 2 being the base of the terms above. hence this can be expressed as ln (1-3x) / ln 2. Since 1 / ln 2 is a constant, we can just carry out this constant beside the derivative of ln (1-3x). the derivative of ln (1-3x) is - 3 / (1-3x). Hence the answer is - 3/ln 2 * (1-3x)