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Mathematics
Ian Armstrong
31 December, 17:16
Evaluate Integral: 2sin (2x) from 0, pi/2
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Matias Harrison
31 December, 20:34
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Integral of 2sin (2x) is - cos (2x)
from 0 to pi/2 (sub pi/2 minus sub 0 for x) and then solve
= - cos (2*pi/2) - (-cos0)
= - cos pi + cos 0
= 1 + 1
= 2
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