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15 July, 13:23

If (x, 0) lies on the graph of y = logbx, then x =

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  1. 15 July, 16:59
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    We have the following expression:

    y = logbx

    We clear x of the expression.

    We have then:

    b ^ y = b ^ (logbx)

    Rewriting:

    x = b ^ y

    Substituting we have:

    x = b ^ 0

    x = 1

    Answer:

    If (x, 0) lies on the graph of y = logbx, then:

    x = 1
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