Ask Question
20 April, 22:05

Urn 1 contains 5 red balls and 3 black balls. Urn 2 contains 3 red balls and 1 black ball. Urn 3 contains 4 red balls and 2 black balls. If an urn is selected at random and a ball is drawn, find the probability it will be red.

+3
Answers (1)
  1. 21 April, 00:48
    0
    Hello,

    Choice urn_1: 1/3

    choice R: 5/8 = = >1/3*5/8=5/24

    Choice urn_2: 1/3

    Choice R: 3/4 = = > 1/3*3/4=1/4

    Choice urn_3: 1/3

    Choice R:4/6=2/3 = = > 1/3*2/3=2/9

    Total: 5/24+1/4+2/9=15/72+18/72+16/72=49/72
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Urn 1 contains 5 red balls and 3 black balls. Urn 2 contains 3 red balls and 1 black ball. Urn 3 contains 4 red balls and 2 black balls. If ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers