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14 September, 04:39

A projectile is thrown upward so that its distance above the ground after t seconds is h (t) = - 16t^2 + 570t. After how many seconds does it reach its maximum height?

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  1. 14 September, 05:52
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    It would only take 1 second to reach maximum height.

    h (1) = - 16 (1^2) + (570) (1) after simplification, h would be 554.

    If you kept increasing t, h would get smaller.
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