Ask Question
1 October, 00:01

Some bullfrogs were introduced into a small pond. The graph shows the bullfrog population for the next few years. Assume that the population grows exponentially.

equation: 140 (315/140) ^ (t/2)

What is the growth rate?

+1
Answers (1)
  1. 1 October, 01:41
    0
    For exponential growths,

    population after time t = original population x (growth rate) ^time

    The growth rate works out to be:

    (315/140) ^ (t/2)

    = [√ (315/140) ]^t

    = 1.5^t

    The growth rate is 1.5 times per year.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Some bullfrogs were introduced into a small pond. The graph shows the bullfrog population for the next few years. Assume that the ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers