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27 December, 20:12

Find the x and y intercepts for y=3x/x^2+9

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Answers (2)
  1. 27 December, 20:38
    0
    So ...

    Y=3x / (x^2+9), plug in 0 for Y.

    0=3x / (x^2+9), multiply both sides by denominator

    0=3x, at y=, x=0. Intercept at origin (:

    For

    Y = (3x/x^2) + 9, plug in 0 for Y

    0 = (3x/x^2) + 9, subtract both sides

    -9 = (3x/x^2), divide by x on the right

    -9=3/x, multiply by x to the other side

    -9x=3, and divide by - 9

    X=-1/3 or -.33333. At x = 0 is null, because it's division by 0 (: so no y Intercept
  2. 27 December, 22:05
    0
    Plug in 0 for x. Plug in 0 for y.
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