Ask Question
17 September, 19:11

What is the value of 81x2y3+z if x=3 y=4 and z=19

+2
Answers (1)
  1. 17 September, 20:37
    0
    Ok first of all I am assuming you mean

    81. (x**2). (y**3) + z = Value

    We just need to simply substitute x, y and z

    81. (3*3) (4*4*4) + 19 = Value

    46656 + 19 = Value ... >> Value = 46675
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “What is the value of 81x2y3+z if x=3 y=4 and z=19 ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers