Which equation has both 4 and? - 4 as possible values of y?

y²=8 y³=12 y²=16 y³=64

The correct answer is y² = 16.

For the first equation, taking the square root of 8 will not give 4 or - 4.

For the second equation, taking the cubed root of 12 will not give 4 or - 4.

For the third equation, the square root of 16 is either 4 or - 4.

For the fourth equation, the cubed root of 64 is positive 4, not - 4.