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Mathematics
Juliet Riddle
29 May, 18:06
Find the samllest value of K when:
280k is a perfect square
882 is a cube
+4
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Paris Garcia
29 May, 19:00
0
280 = 7 x 2^3 x 5
882 = 7^2 x 2 x 3^2
For 280k to be perfect square, their powers need to be even
For 882 to be a cube, their powers need to be in multiple of 3,
To satisfy both parties,
K = 7 x 2^5 x 3^4 x 5^3 = 2268000
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