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29 May, 18:06

Find the samllest value of K when:

280k is a perfect square

882 is a cube

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Answers (1)
  1. 29 May, 19:00
    0
    280 = 7 x 2^3 x 5

    882 = 7^2 x 2 x 3^2

    For 280k to be perfect square, their powers need to be even

    For 882 to be a cube, their powers need to be in multiple of 3,

    To satisfy both parties,

    K = 7 x 2^5 x 3^4 x 5^3 = 2268000
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