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16 January, 10:10

The length of a rectangle is 3 ft more than twice the width, and the area of the rectangle is 54 ft2. find the dimensions of the rectangle.

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  1. 16 January, 10:40
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    A = L * W

    A = 54

    L = 2W + 3

    54 = W (2W + 3)

    54 = 2W^2 + 3W

    2W^2 + 3W - 54 = 0

    (2W - 9) (W + 6) = 0

    2W - 9 = 0

    2W = 9

    W = 9/2

    W = 4.5 < = = width

    W + 6 = 0

    W = - 6 ... it wont be this one because it is negative

    L = 2W + 3

    L = 2 (4.5) + 3

    L = 9 + 3

    L = 12 <==length
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